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LetsGit.IT/Categories/Data Structures
Data Structuresmedium

What is an LRU cache and how can you implement it in O(1)?

Tags
#lru#cache#hashmap#linked-list#big-o
Back to categoryPractice quiz

Answer

LRU (Least Recently Used) evicts the item that hasn’t been used for the longest time. A common O(1) design is: HashMap for key→node lookup + doubly linked list to move items to the front on access and evict from the tail.

type Node = { key: string; prev?: Node; next?: Node }

// idea:
// map: key -> node
// list: head <-> ... <-> tail
// get(key): move node to head (O(1))
// put(key): insert/move to head; if over capacity, evict tail (O(1))

Advanced answer

Deep dive

Expanding on the short answer — what usually matters in practice:

  • Context (tags): lru, cache, hashmap, linked-list, big-o
  • Complexity: compare typical operations (average vs worst-case).
  • Invariants: what must always hold for correctness.
  • When the choice is wrong: production symptoms (latency, GC, cache misses).
  • Explain the "why", not just the "what" (intuition + consequences).
  • Trade-offs: what you gain/lose (time, memory, complexity, risk).
  • Edge cases: empty inputs, large inputs, invalid inputs, concurrency.

Examples

Here’s an additional example (building on the short answer):

type Node = { key: string; prev?: Node; next?: Node }

// idea:
// map: key -> node
// list: head <-> ... <-> tail
// get(key): move node to head (O(1))
// put(key): insert/move to head; if over capacity, evict tail (O(1))

Common pitfalls

  • Too generic: no concrete trade-offs or examples.
  • Mixing average-case and worst-case (e.g., complexity).
  • Ignoring constraints: memory, concurrency, network/disk costs.

Interview follow-ups

  • When would you choose an alternative and why?
  • What production issues show up and how do you diagnose them?
  • How would you test edge cases?

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