A* uses f(n) = g(n) + h(n). If the heuristic h is admissible (never overestimates) and consistent, A* is optimal and explores fewer nodes than Dijkstra. If h overestimates, optimality is not guaranteed. With h = 0, A* reduces to Dijkstra.
Expanding on the short answer — what usually matters in practice:
A tiny example (an explanation template):
// Example: discuss trade-offs for "a*-search:-how-does-the-heuristic-affect-optimal"
function explain() {
// Start from the core idea:
// A* uses f(n) = g(n) + h(n). If the heuristic h is admissible (never overestimates) and con
}