A* uses f(n) = g(n) + h(n). If the heuristic h is admissible (never overestimates) and consistent, A* is optimal and explores fewer nodes than Dijkstra. If h overestimates, optimality is not guaranteed. With h = 0, A* reduces to Dijkstra.
Advanced answer
Deep dive
Expanding on the short answer — what usually matters in practice:
Complexity: compare typical operations (average vs worst-case).
Invariants: what must always hold for correctness.
When the choice is wrong: production symptoms (latency, GC, cache misses).
Explain the "why", not just the "what" (intuition + consequences).
Trade-offs: what you gain/lose (time, memory, complexity, risk).
Edge cases: empty inputs, large inputs, invalid inputs, concurrency.
Examples
A tiny example (an explanation template):
// Example: discuss trade-offs for "a*-search:-how-does-the-heuristic-affect-optimal"
function explain() {
// Start from the core idea:
// A* uses f(n) = g(n) + h(n). If the heuristic h is admissible (never overestimates) and con
}
Common pitfalls
Too generic: no concrete trade-offs or examples.
Mixing average-case and worst-case (e.g., complexity).