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LetsGit.IT/Categories/Algorithms
Algorithmsmedium

Counting sort: when can it be faster than O(n log n) sorting?

Tags
#counting-sort#sorting#stability#big-o
Back to categoryPractice quiz

Answer

Counting sort is good when keys are integers in a small range 0..k. It runs in O(n + k) by counting occurrences and building the output, and it can be stable (useful as a building block for radix sort).

Advanced answer

Deep dive

Expanding on the short answer — what usually matters in practice:

  • Context (tags): counting-sort, sorting, stability, big-o
  • Complexity: compare typical operations (average vs worst-case).
  • Invariants: what must always hold for correctness.
  • When the choice is wrong: production symptoms (latency, GC, cache misses).
  • Explain the "why", not just the "what" (intuition + consequences).
  • Trade-offs: what you gain/lose (time, memory, complexity, risk).
  • Edge cases: empty inputs, large inputs, invalid inputs, concurrency.

Examples

A tiny example (an explanation template):

// Example: discuss trade-offs for "counting-sort:-when-can-it-be-faster-than-o(n-lo"
function explain() {
  // Start from the core idea:
  // Counting sort is good when keys are integers in a small range 0..k. It runs in O(n + k) by
}

Common pitfalls

  • Too generic: no concrete trade-offs or examples.
  • Mixing average-case and worst-case (e.g., complexity).
  • Ignoring constraints: memory, concurrency, network/disk costs.

Interview follow-ups

  • When would you choose an alternative and why?
  • What production issues show up and how do you diagnose them?
  • How would you test edge cases?

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